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Popular >

y^{''}+4y=0

Solution

y^{^{''}} + 4 y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

y^{''} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Popular Examples

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area x^3,x area

x^{3}, x

derivative of 7x^3e^x derivative of

7 x^{3} e^{x}

tangent of f(x)=-1/((x-5)^2),\at x=-4 tangent of

f (x) = - \frac{1}{( x - 5 ) ^{2}}, at x = - 4

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y=0 ?
The solution for y^{''}+4y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)