What is the limit as z approaches+0 of (2z-8) 1/3 ?

The limit as z approaches+0 of (2z-8) 1/3 is -8/3

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limit as z approaches+0 of (2z-8) 1/3

z \to + 0 lim ((2 z - 8) \frac{1}{3})

- \frac{8}{3}

Decimal Notation

- 2.66666 \dots

Solution steps

z \to 0 lim ((2 z - 8) \frac{1}{3})

Plug in the value

z = 0

= (2 \cdot 0 - 8) \frac{1}{3}

Simplify

(2 \cdot 0 - 8) \frac{1}{3} : - \frac{8}{3}

= - \frac{8}{3}

x \to 0 lim (\frac{- 1 + e ^{x}}{x})

x \to 2 lim (x^{3} + 2)

x \to - 5 lim (- 1)

x \to 2 lim (x^{2} + 4 x - 10)

x \to \infty lim (x (\frac{1}{x}))

What is the limit as z approaches+0 of (2z-8) 1/3 ?
The limit as z approaches+0 of (2z-8) 1/3 is -8/3