What is the limit as x approaches 0 of+(cos(2x)) 1/x ?

The limit as x approaches 0 of+(cos(2x)) 1/x is diverges

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limit as x approaches 0 of+(cos(2x)) 1/x

x \to 0 lim (+ (cos (2 x)) \frac{1}{x})

diverges

Solution steps

x \to 0 lim (cos (2 x) \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (cos (2 x) \frac{1}{x}) = \infty

x \to 0 - lim (cos (2 x) \frac{1}{x}) = - \infty

= diverges

x \to 0 lim (\frac{1}{x} ln (x))

x \to 0 lim (\frac{( sin ( 5 x ) )}{sin ( 4 x )})

x \to 6 - lim (\frac{x - [ x ]}{x - 6})

x \to 0 lim (\frac{1}{e ^{- x} - 1})

x \to 0 lim (x cos^{2} (\frac{1}{2}))

What is the limit as x approaches 0 of+(cos(2x)) 1/x ?
The limit as x approaches 0 of+(cos(2x)) 1/x is diverges