What is the derivative of 3+cos(x) ?

The derivative of 3+cos(x) is -sin(x)

What is the first derivative of 3+cos(x) ?

The first derivative of 3+cos(x) is -sin(x)

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\frac{d}{d x} (3 + cos (x))

- sin (x)

Solution steps

\frac{d}{d x} (3 + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (cos (x)) = - sin (x)

= 0 - sin (x)

Simplify

= - sin (x)

n = 0 \sum \infty e^{- n} + 1

\int \frac{x}{4 + x ^{2}} d x

\frac{x ^{5} + e ^{x}}{x + 2}

f (x) = 4 x^{\frac{1}{2}} + 8 x^{\frac{3}{2}} + 9, at x = 4

\int_{e}^{\infty} x^{0} ln (x) d x

What is the derivative of 3+cos(x) ?
The derivative of 3+cos(x) is -sin(x)
What is the first derivative of 3+cos(x) ?
The first derivative of 3+cos(x) is -sin(x)