What is the limit as x approaches-infinity of 4e^x ?

The limit as x approaches-infinity of 4e^x is 0

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limit as x approaches-infinity of 4e^x

x \to - \infty lim (4 e^{x})

0

Solution steps

x \to - \infty lim (4 e^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 4 \cdot x \to - \infty lim (e^{x})

Apply the common limit:

x \to - \infty lim (e^{x}) = 0

= 4 \cdot 0

Simplify

= 0

x \to - 6 + lim (\frac{∣ x + 6 ∣}{x + 6})

x \to \infty lim (\frac{e ^{x} + sin ( x )}{e ^{x} + cos ( x )})

x \to 1 lim (\frac{x + 2}{x ^{2} - 1})

x \to 1 + lim (x^{2} + 2)

x \to 2 lim (3 x^{2} + 8 x - 1)

What is the limit as x approaches-infinity of 4e^x ?
The limit as x approaches-infinity of 4e^x is 0