What is the limit as θ approaches pi/2 of 5θsin(θ) ?

The limit as θ approaches pi/2 of 5θsin(θ) is 5*pi/2

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limit as θ approaches pi/2 of 5θsin(θ)

θ \to \frac{π}{2} lim (5 θ sin (θ))

5 \cdot \frac{π}{2}

Decimal

7.85398 \dots

Solution steps

θ \to \frac{π}{2} lim (5 θ sin (θ))

Plug in the value

θ = \frac{π}{2}

= 5 \cdot \frac{π}{2} sin (\frac{π}{2})

Simplify

5 \cdot \frac{π}{2} sin (\frac{π}{2}) : 5 \cdot \frac{π}{2}

= 5 \cdot \frac{π}{2}

x \to - 2 lim (\frac{1}{2 ^{x} - \frac{1}{4}})

x \to 1 lim (\frac{1}{2 x})

x \to - 2 l n (2) lim (x^{10})

t \to 0 lim (t (v (t)))

x \to 0 lim (2 - \frac{sin ( 4 x )}{x})

What is the limit as θ approaches pi/2 of 5θsin(θ) ?
The limit as θ approaches pi/2 of 5θsin(θ) is 5*pi/2