What is the derivative of (-3/(x^2)) ?

The derivative of (-3/(x^2)) is 6/(x^3)

What is the first derivative of (-3/(x^2)) ?

The first derivative of (-3/(x^2)) is 6/(x^3)

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\frac{d}{d x} (\frac{- 3}{x ^{2}})

\frac{6}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 3}{x ^{2}})

Simplify

\frac{- 3}{x ^{2}} : - \frac{3}{x ^{2}}

= \frac{d}{d x} (- \frac{3}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 3 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 (- 2 x^{- 2 - 1})

Simplify

- 3 (- 2 x^{- 2 - 1}) : \frac{6}{x ^{3}}

= \frac{6}{x ^{3}}

\int (\frac{1}{x ^{3}}) d x

\int x^{n + 1} d x

\int x sin (\frac{1}{5} x) d x

2 x - 4

\int_{2}^{5} t^{2} ln (3 t) d t

What is the derivative of (-3/(x^2)) ?
The derivative of (-3/(x^2)) is 6/(x^3)
What is the first derivative of (-3/(x^2)) ?
The first derivative of (-3/(x^2)) is 6/(x^3)