What is the limit as x approaches 0+of (1+2x)^{2/x} ?

The limit as x approaches 0+of (1+2x)^{2/x} is e^4

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limit as x approaches 0+of (1+2x)^{2/x}

x \to 0 + lim ((1 + 2 x)^{\frac{2}{x}})

e^{4}

Decimal Notation

54.59815 \dots

Solution steps

x \to 0 + lim ((1 + 2 x)^{\frac{2}{x}})

Apply exponent rules

= x \to 0 + lim (e^{\frac{2}{x} l n (1 + 2 x)})

Apply the Limit Chain Rule:

e^{4}

= e^{4}

t \to 0 lim (- 5 e^{t})

x \to a lim (\frac{2 ( - 3 )}{8 - 0})

x \to 0 + lim ((1 - 2 x)^{\frac{9}{x}})

x \to 0 + lim ((- 4 ln (x))^{x})

x \to 0 lim (\frac{( 1 - x ) ^{4} - 1}{x})

What is the limit as x approaches 0+of (1+2x)^{2/x} ?
The limit as x approaches 0+of (1+2x)^{2/x} is e^4