What is the limit as x approaches 0 of x^2ln(x^2+x) ?

The limit as x approaches 0 of x^2ln(x^2+x) is Does not exist

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limit as x approaches 0 of x^2ln(x^2+x)

x \to 0 lim (x^{2} ln (x^{2} + x))

Does not exist

Solution steps

x \to 0 lim (x^{2} ln (x^{2} + x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{2} ln (x^{2} + x)) = 0

x \to 0 - lim (x^{2} ln (x^{2} + x)) =

Does not exist

= Does not exist

x \to 0 + lim (7 (cot (x) - \frac{1}{x}))

x \to 0 + lim (ln (1) - ln (x))

x \to 0 + lim (b (0)^{2} + ab)

x \to 3 lim (x - [x])

x \to - 3 lim (1 - 5 x)

What is the limit as x approaches 0 of x^2ln(x^2+x) ?
The limit as x approaches 0 of x^2ln(x^2+x) is Does not exist