What is the limit as x approaches 2pi of x/(sin(x)) ?

The limit as x approaches 2pi of x/(sin(x)) is diverges

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limit as x approaches 2pi of x/(sin(x))

x \to 2 π lim (\frac{x}{sin ( x )})

diverges

Solution steps

x \to 2 π lim (\frac{x}{sin ( x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 π + lim (\frac{x}{sin ( x )}) = \infty

x \to 2 π - lim (\frac{x}{sin ( x )}) = - \infty

= diverges

x \to 0 lim (\frac{x ^{3}}{x})

x \to 0 lim (\frac{1 + x}{2 x})

x \to 5 lim (\frac{x + 3}{x ^{2} - 9})

x \to 0 lim (\frac{2}{x ( x - 2 )})

x \to 0 lim (\frac{7 ^{x} - 8 ^{x}}{x})

What is the limit as x approaches 2pi of x/(sin(x)) ?
The limit as x approaches 2pi of x/(sin(x)) is diverges