What is the derivative of (2t^2-1)^3 ?

The derivative of (2t^2-1)^3 is 12t(2t^2-1)^2

What is the first derivative of (2t^2-1)^3 ?

The first derivative of (2t^2-1)^3 is 12t(2t^2-1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(2 t^{2} - 1)^{3}

12 t (2 t^{2} - 1)^{2}

Solution steps

\frac{d}{d t} ((2 t^{2} - 1)^{3})

Apply the chain rule:

3 (2 t^{2} - 1)^{2} \frac{d}{d t} (2 t^{2} - 1)

= 3 (2 t^{2} - 1)^{2} \frac{d}{d t} (2 t^{2} - 1)

\frac{d}{d t} (2 t^{2} - 1) = 4 t

= 3 (2 t^{2} - 1)^{2} \cdot 4 t

Simplify

= 12 t (2 t^{2} - 1)^{2}

x \to 3 lim (x - 13)

\frac{d y}{d x} = y + x, y (1) = 2

x \to 0 lim (x arctan (\frac{1}{x}))

\frac{d}{d x} ((e^{3 x} + 1)^{2})

3 t sec (t)

What is the derivative of (2t^2-1)^3 ?
The derivative of (2t^2-1)^3 is 12t(2t^2-1)^2
What is the first derivative of (2t^2-1)^3 ?
The first derivative of (2t^2-1)^3 is 12t(2t^2-1)^2