What is the limit as x approaches 4 of-1/(x^2-16) ?

The limit as x approaches 4 of-1/(x^2-16) is diverges

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limit as x approaches 4 of-1/(x^2-16)

x \to 4 lim (- \frac{1}{x ^{2} - 16})

diverges

Solution steps

x \to 4 lim (- \frac{1}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (- \frac{1}{x ^{2} - 16}) = - \infty

x \to 4 - lim (- \frac{1}{x ^{2} - 16}) = \infty

= diverges

x \to 0 lim (\frac{sin ^{2} ( 8 x )}{x})

k \to \infty lim (ln (k))

x \to 1 lim (\frac{12}{x + 9})

x \to \frac{1}{4} lim (3 4 x + 8)

x \to - 5 lim ((x^{2} + 1)^{\frac{1}{3}})

What is the limit as x approaches 4 of-1/(x^2-16) ?
The limit as x approaches 4 of-1/(x^2-16) is diverges