What is the limit as x approaches infinity of-e^{+x} ?

The limit as x approaches infinity of-e^{+x} is -infinity

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limit as x approaches infinity of-e^{+x}

x \to \infty lim (- e^{+ x})

- \infty

Solution steps

x \to \infty lim (- e^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (e^{x})

Apply the common limit:

x \to \infty lim (e^{x}) = \infty

= - \infty

x \to 0 lim (5 x^{x})

x \to 0 lim (\frac{1}{ln ( x ^{2} )})

x \to 0 lim (x^{2} - 3 e^{x})

x \to 4 lim (2 x - 9)

x \to 0 lim (2 x^{2} \cdot ln (x))

What is the limit as x approaches infinity of-e^{+x} ?
The limit as x approaches infinity of-e^{+x} is -infinity