What is the limit as t approaches 2 of tan^2(pi/8 t) ?

The limit as t approaches 2 of tan^2(pi/8 t) is 1

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limit as t approaches 2 of tan^2(pi/8 t)

t \to 2 lim (tan^{2} (\frac{π}{8} t))

1

Solution steps

t \to 2 lim (tan^{2} (\frac{π}{8} t))

Plug in the value

t = 2

= tan^{2} (\frac{π}{8} \cdot 2)

Simplify

tan^{2} (\frac{π}{8} \cdot 2) : 1

= 1

x \to 0 lim (4 x - 1)

x \to 7 lim (8 x + 4)

x \to - 2 lim (\frac{10 + 5 x}{x - 2})

x \to 3 lim (\frac{5 x - 6}{4 x + 3})

What is the limit as t approaches 2 of tan^2(pi/8 t) ?
The limit as t approaches 2 of tan^2(pi/8 t) is 1