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Popular >

x^2y^'+xy=1,y(1)=2

Solution

x^{2} y^{^{'}} + x y = 1, y (1) = 2

Solution

y = \frac{ln ( x )}{x} + \frac{2}{x}

Solution steps

x^{2} y^{'} (x) + x y = 1

Solve linear ODE:

y = \frac{ln ( x )}{x} + \frac{2}{x}

y = \frac{ln ( x )}{x} + \frac{2}{x}

Popular Examples

derivative of 22e^{x^2}x derivative of

22 e^{x^{2}} x

sum from n=0 to infinity of ((9^n))/(n!)

n = 0 \sum \infty \frac{( 9 ^{n} )}{n !}

integral of (x+3)/(x^2+2x+2)

\int \frac{x + 3}{x ^{2} + 2 x + 2} d x

integral from 0 to 2 of sqrt(e^x)

\int_{0}^{2} e^{x} d x

area x^2+1,x+3,0 area

x^{2} + 1, x + 3, 0

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+xy=1,y(1)=2 ?
The solution for x^2y^'+xy=1,y(1)=2 is y=(ln(x))/x+2/x