What is the limit as (x) approaches (0) of 1/x ?

The limit as (x) approaches (0) of 1/x is diverges

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limit as (x) approaches (0) of 1/x

(x) \to (0) lim (\frac{1}{x})

diverges

Solution steps

x \to 0 lim (\frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x}) = \infty

x \to 0 - lim (\frac{1}{x}) = - \infty

= diverges

x \to 0 lim (\frac{x}{4} sin (\frac{1}{x}))

x \to \frac{π}{2} lim (2 cos (x))

h \to 0 lim ((1 + 4 h)^{\frac{1}{h}})

x \to 3 lim (\frac{e ^{x} - 1}{x})

x \to 0 lim (+ (x e^{\frac{1}{x}}))

What is the limit as (x) approaches (0) of 1/x ?
The limit as (x) approaches (0) of 1/x is diverges