What is the limit as x approaches 0-of ln(1+x) ?

The limit as x approaches 0-of ln(1+x) is 0

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limit as x approaches 0-of ln(1+x)

x \to 0 - lim (ln (1 + x))

0

Solution steps

x \to 0 - lim (ln (1 + x))

Plug in the value

x = 0

= ln (1 + 0)

Simplify

ln (1 + 0) : 0

= 0

x \to 5 lim (6 x - 14)

x \to 0 + lim ((5 tan (x))^{x})

x \to 2 lim (4 x^{2} - x + 5)

x \to 0 + lim ((1 + 5 x)^{\frac{3}{x}})

x \to 4 lim (2 x^{2} - 3 x + 40)

What is the limit as x approaches 0-of ln(1+x) ?
The limit as x approaches 0-of ln(1+x) is 0