What is laplacetransform sin^2(5t) ?

The answer to laplacetransform sin^2(5t) is (50)/(s(s^2+100))

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laplacetransform sin^2(5t)

laplace transform

sin^{2} (5 t)

\frac{50}{s ( s ^{2} + 100 )}

Solution steps

L {sin^{2} (5 t)}

Rewrite using trig identities

L {\frac{1}{2} - \frac{1}{2} cos (10 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {\frac{1}{2}} - \frac{1}{2} L {cos (10 t)}

L {\frac{1}{2}} : \frac{1}{2 s}

L {cos (10 t)} : \frac{s}{s ^{2} + 100}

= \frac{1}{2 s} - \frac{1}{2} \cdot \frac{s}{s ^{2} + 100}

Simplify

\frac{1}{2 s} - \frac{1}{2} \frac{s}{s ^{2} + 100} : \frac{50}{s ( s ^{2} + 100 )}

= \frac{50}{s ( s ^{2} + 100 )}

\int \frac{sin ( x ) + cos ^{2} ( x )}{cos ^{2} ( x )} d x

f (x) = \frac{6}{x}, (1, 6)

\int e^{x + 3 y} d x

\int \frac{sec ^{4} ( x )}{tan ( x )} d x

y = x^{3} - 6 x, (0, 3)

What is laplacetransform sin^2(5t) ?
The answer to laplacetransform sin^2(5t) is (50)/(s(s^2+100))