What is the limit as x approaches 2 of log_{2}(x+2) ?

The limit as x approaches 2 of log_{2}(x+2) is 2

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limit as x approaches 2 of log_{2}(x+2)

x \to 2 lim (lo g_{2} (x + 2))

2

Solution steps

x \to 2 lim (lo g_{2} (x + 2))

Plug in the value

x = 2

= lo g_{2} (2 + 2)

Simplify

lo g_{2} (2 + 2) : 2

= 2

x \to 0 lim (x^{2} cos (10 x))

x \to - 4 lim (1)

x \to 1 + lim (\frac{( x ^{2} )}{x - 1})

x \to 0 lim (ln (x + 2))

t \to 0 lim (\frac{e ^{t}}{ln ( t )})

What is the limit as x approaches 2 of log_{2}(x+2) ?
The limit as x approaches 2 of log_{2}(x+2) is 2