What is the limit as x approaches 2 of 8/(x^2-4) ?

The limit as x approaches 2 of 8/(x^2-4) is diverges

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limit as x approaches 2 of 8/(x^2-4)

x \to 2 lim (\frac{8}{x ^{2} - 4})

diverges

Solution steps

x \to 2 lim (\frac{8}{x ^{2} - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{8}{x ^{2} - 4}) = \infty

x \to 2 - lim (\frac{8}{x ^{2} - 4}) = - \infty

= diverges

x \to 2 + lim (2 x - 1)

x \to 31 + lim (x (31))

x \to a lim ((f (x))^{n})

x \to 0 lim (6 (cot (x) - \frac{1}{x}))

x \to 3 lim (\frac{- 1}{x - 3})

What is the limit as x approaches 2 of 8/(x^2-4) ?
The limit as x approaches 2 of 8/(x^2-4) is diverges