What is the limit as x approaches infinity of 9/(2x) ?

The limit as x approaches infinity of 9/(2x) is 0

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limit as x approaches infinity of 9/(2x)

x \to \infty lim (\frac{9}{2 x})

0

Solution steps

x \to \infty lim (\frac{9}{2 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{9}{2} \cdot x \to \infty lim (\frac{1}{x})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{9}{2} \cdot \frac{lim _{x \to \infty} ( 1 )}{lim _{x \to \infty} ( x )}

x \to \infty lim (1) = 1

x \to \infty lim (x) = \infty

= \frac{9}{2} \cdot \frac{1}{\infty}

Simplify

\frac{9}{2} \cdot \frac{1}{\infty} : 0

= 0

x \to 2 lim (2 x^{2} + 5 x - 2)

x \to 0 + lim ((3 x + 1)^{\frac{1}{x}})

x \to - \infty lim (0 - (x))

x \to 5 - lim (\frac{x + 2}{x + 5})

x \to 15 lim (x)

What is the limit as x approaches infinity of 9/(2x) ?
The limit as x approaches infinity of 9/(2x) is 0