What is the limit as x approaches pi/2 of sin(2x+pi) ?

The limit as x approaches pi/2 of sin(2x+pi) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches pi/2 of sin(2x+pi)

x \to \frac{π}{2} lim (sin (2 x + π))

0

Solution steps

x \to \frac{π}{2} lim (sin (2 x + π))

Plug in the value

x = \frac{π}{2}

= sin (2 \cdot \frac{π}{2} + π)

Simplify

sin (2 \cdot \frac{π}{2} + π) : 0

= 0

x \to 0 lim (csc (x) - tan (x))

x \to 3 - lim (\frac{x - 1}{x - 1})

x \to 4 lim (\frac{x ^{2} - 6}{x + 2})

x \to - 2 lim (x^{2} + 3 x - 3)

x \to 31 lim (31 - x)

What is the limit as x approaches pi/2 of sin(2x+pi) ?
The limit as x approaches pi/2 of sin(2x+pi) is 0