What is the solution for y^'=(0.5+sin(t))(y/5) ?

The solution for y^'=(0.5+sin(t))(y/5) is y=e^{0.2(0.5t-cos(t))+c_{1}}

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y^'=(0.5+sin(t))(y/5)

y^{^{'}} = (0.5 + sin (t)) (\frac{y}{5})

y = e^{0.2 (0.5 t - c o s (t)) + c_{1}}

Solution steps

y^{'} (t) = (0.5 + sin (t)) (\frac{y}{5})

Solve separable ODE:

y = e^{0.2 (0.5 t - c o s (t)) + c_{1}}

y = e^{0.2 (0.5 t - c o s (t)) + c_{1}}

e^{- x}, x = 0

\int \frac{1}{x x - 4} d x

\int sec^{4} (\frac{x}{3}) d x

y = x^{2} e^{x} - 2 x e^{x} + 5 e^{x}

What is the solution for y^'=(0.5+sin(t))(y/5) ?
The solution for y^'=(0.5+sin(t))(y/5) is y=e^{0.2(0.5t-cos(t))+c_{1}}