What is the limit as x approaches 2 of 2x^2-5x+6 ?

The limit as x approaches 2 of 2x^2-5x+6 is 4

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limit as x approaches 2 of 2x^2-5x+6

x \to 2 lim (2 x^{2} - 5 x + 6)

4

Solution steps

x \to 2 lim (2 x^{2} - 5 x + 6)

Plug in the value

x = 2

= 2 \cdot 2^{2} - 5 \cdot 2 + 6

Simplify

2 \cdot 2^{2} - 5 \cdot 2 + 6 : 4

= 4

h \to 0 lim (\frac{6}{h})

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x \to 0 lim (x^{0} \cdot sin (\frac{1}{x}))

t \to 0 + lim (\frac{2}{t} - \frac{1}{e ^{t} - 1})

x \to 0 lim (\frac{( 1 - x ) ^{5} - 1}{x})

What is the limit as x approaches 2 of 2x^2-5x+6 ?
The limit as x approaches 2 of 2x^2-5x+6 is 4