What is the limit as x approaches-0 of (e^2-1)/x ?

The limit as x approaches-0 of (e^2-1)/x is diverges

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limit as x approaches-0 of (e^2-1)/x

x \to - 0 lim (\frac{e ^{2} - 1}{x})

diverges

Solution steps

x \to - 0 lim (\frac{e ^{2} - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 0 + lim (\frac{e ^{2} - 1}{x}) = \infty

x \to - 0 - lim (\frac{e ^{2} - 1}{x}) = - \infty

= diverges

x \to \infty lim (\frac{4}{2})

x \to - \infty lim (3 x^{3} - 4)

x \to 0 lim (x lo g_{2} (\frac{1}{x}))

x \to 0 + lim ((1 - 7 x)^{\frac{3}{x}})

x \to 0 lim (\frac{1}{x cos ( x )})

What is the limit as x approaches-0 of (e^2-1)/x ?
The limit as x approaches-0 of (e^2-1)/x is diverges