What is the limit as x approaches (0) of (3xy)/(5x^2+2y^2) ?

The limit as x approaches (0) of (3xy)/(5x^2+2y^2) is 0

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limit as x approaches (0) of (3xy)/(5x^2+2y^2)

x \to (0) lim (\frac{3 x y}{5 x ^{2} + 2 y ^{2}})

0

Solution steps

x \to 0 lim (\frac{3 x y}{5 x ^{2} + 2 y ^{2}})

Plug in the value

x = 0

= \frac{3 \cdot 0 \cdot y}{5 \cdot 0 ^{2} + 2 y ^{2}}

Simplify

\frac{3 \cdot 0 \cdot y}{5 \cdot 0 ^{2} + 2 y ^{2}} : 0

= 0

x \to 3 lim ((x^{2}) (x + 3))

x \to - \infty lim (3 x - 2)

x \to 7 - lim (\frac{1}{( x - 7 ) ^{2}})

x \to 4 lim (k x + 1)

x \to 1 - lim (\frac{1 - x}{∣ 1 - x ∣})

What is the limit as x approaches (0) of (3xy)/(5x^2+2y^2) ?
The limit as x approaches (0) of (3xy)/(5x^2+2y^2) is 0