What is the limit as x approaches 0-of 1/x+x ?

The limit as x approaches 0-of 1/x+x is -infinity

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limit as x approaches 0-of 1/x+x

x \to 0 - lim (\frac{1}{x} + x)

- \infty

Solution steps

x \to 0 - lim (\frac{1}{x} + x)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (\frac{1}{x}) + x \to 0 - lim (x)

x \to 0 - lim (\frac{1}{x}) = - \infty

x \to 0 - lim (x) = 0

= - \infty + 0

Apply Infinity Property:

- \infty + c = - \infty

= - \infty

x \to 0 - lim (\frac{ln ∣ x ∣}{x})

x \to 0 lim (x^{- 2} (x - 3)^{3})

x \to 2 lim (x^{2} + 6 x + 2)

t \to 0 + lim (ln (t))

x \to 3 lim (\frac{4 x - 4}{x - 3})

What is the limit as x approaches 0-of 1/x+x ?
The limit as x approaches 0-of 1/x+x is -infinity