What is the limit as x approaches 0 of sin(4x)ln(x) ?

The limit as x approaches 0 of sin(4x)ln(x) is Does not exist

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limit as x approaches 0 of sin(4x)ln(x)

x \to 0 lim (sin (4 x) ln (x))

Does not exist

Solution steps

x \to 0 lim (sin (4 x) ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (sin (4 x) ln (x)) = 0

x \to 0 - lim (sin (4 x) ln (x)) =

Does not exist

= Does not exist

x \to 0 lim (\frac{1 - x}{x})

x \to 3 - lim (\frac{x - 3}{x})

x \to 0 - lim (\frac{x - ∣ x ∣}{x})

x \to 1 + lim (\frac{1 - x}{∣ 1 - x ∣})

x \to 3 lim (3 - 3 x)

What is the limit as x approaches 0 of sin(4x)ln(x) ?
The limit as x approaches 0 of sin(4x)ln(x) is Does not exist