What is the limit as x approaches infinity of 1+e^x ?

The limit as x approaches infinity of 1+e^x is infinity

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limit as x approaches infinity of 1+e^x

x \to \infty lim (1 + e^{x})

\infty

Solution steps

x \to \infty lim (1 + e^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (1) + x \to \infty lim (e^{x})

x \to \infty lim (1) = 1

x \to \infty lim (e^{x}) = \infty

= 1 + \infty

Apply Infinity Property:

c + \infty = \infty

= \infty

x \to 2 lim (\frac{( x - 2 )}{( x - 1 - 3 - x )})

f (x) = x - x^{3}, at x = 1

5 x y

f (x) = (5 x + 2)^{\frac{1}{3}}, at x = 2

\int_{0}^{1} (x^{2} + 4) e^{- x} d x

What is the limit as x approaches infinity of 1+e^x ?
The limit as x approaches infinity of 1+e^x is infinity