What is the limit as x approaches 0 of 1/x-1/(2x^2) ?

The limit as x approaches 0 of 1/x-1/(2x^2) is -infinity

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limit as x approaches 0 of 1/x-1/(2x^2)

x \to 0 lim (\frac{1}{x} - \frac{1}{2 x ^{2}})

- \infty

Solution steps

x \to 0 lim (\frac{1}{x} - \frac{1}{2 x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{1}{x} - \frac{1}{2 x ^{2}}) = - \infty

x \to 0 + lim (\frac{1}{x} - \frac{1}{2 x ^{2}}) = - \infty

= - \infty

x \to - 1 lim (3 x^{2})

x \to - \infty lim (ln (1))

t \to 0 lim (ln (1 - t))

x \to - 4 - lim (g (x))

t \to 1 lim (\frac{1}{t})

What is the limit as x approaches 0 of 1/x-1/(2x^2) ?
The limit as x approaches 0 of 1/x-1/(2x^2) is -infinity