What is the derivative of 1/(t^3) ?

The derivative of 1/(t^3) is -3/(t^4)

What is the first derivative of 1/(t^3) ?

The first derivative of 1/(t^3) is -3/(t^4)

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derivative of

\frac{1}{t ^{3}}

- \frac{3}{t ^{4}}

Solution steps

\frac{d}{d t} (\frac{1}{t ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 t^{- 3 - 1}

Simplify

- 3 t^{- 3 - 1} : - \frac{3}{t ^{4}}

= - \frac{3}{t ^{4}}

11

e^{\cdot \frac{1}{4} t}

\int in sec (x) tan (x) d x

9 y^{^{''}} + y = 0, y (\frac{3 π}{2}) = 6, y (0) = - 8

x + y = 0, x = y^{2} + 3 y

What is the derivative of 1/(t^3) ?
The derivative of 1/(t^3) is -3/(t^4)
What is the first derivative of 1/(t^3) ?
The first derivative of 1/(t^3) is -3/(t^4)