What is the solution for f^'(x)=(9x-2)/(8x+7) ?

The solution for f^'(x)=(9x-2)/(8x+7) is f(x)= 9/8 x-79/64 ln(8x+7)+c_{1}

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f^'(x)=(9x-2)/(8x+7)

f^{^{'}} (x) = \frac{9 x - 2}{8 x + 7}

f (x) = \frac{9}{8} x - \frac{79}{64} ln (8 x + 7) + c_{1}

Solution steps

f^{'} (x) = \frac{9 x - 2}{8 x + 7}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{9 x - 2}{8 x + 7} d x

\int \frac{9 x - 2}{8 x + 7} d x = \frac{9}{8} x - \frac{79}{64} ln (8 x + 7) + c_{1}

f (x) = \frac{9}{8} x - \frac{79}{64} ln (8 x + 7) + c_{1}

\frac{d}{d x} (a x e^{- 2 x})

\frac{d y}{d x} = \frac{x + 1}{e ^{3 y + 9}}

x \to 2 lim ((10 - 3 x)^{2})

\int_{1}^{36} e^{x} d x

y = \frac{9}{9 x - x ^{2}}, x = 1, x = 7.5

What is the solution for f^'(x)=(9x-2)/(8x+7) ?
The solution for f^'(x)=(9x-2)/(8x+7) is f(x)= 9/8 x-79/64 ln(8x+7)+c_{1}