What is the limit as x approaches-1 of 1/((x^2-1)) ?

The limit as x approaches-1 of 1/((x^2-1)) is diverges

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limit as x approaches-1 of 1/((x^2-1))

x \to - 1 lim (\frac{1}{( x ^{2} - 1 )})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x ^{2} - 1}) = - \infty

x \to - 1 - lim (\frac{1}{x ^{2} - 1}) = \infty

= diverges

x \to 3 lim (\frac{x ^{2} + 3 x + 3}{x})

x \to 3 lim (\frac{x}{x + 1})

x \to 1 lim (- (x + 1))

x \to - 10 lim (x^{- 2} + 2)

x \to 3 lim (2^{x} x^{2})

What is the limit as x approaches-1 of 1/((x^2-1)) ?
The limit as x approaches-1 of 1/((x^2-1)) is diverges