What is the limit as k approaches infinity of 1+3/k ?

The limit as k approaches infinity of 1+3/k is 1

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limit as k approaches infinity of 1+3/k

k \to \infty lim (1 + \frac{3}{k})

1

Solution steps

k \to \infty lim (1 + \frac{3}{k})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= k \to \infty lim (1) + k \to \infty lim (\frac{3}{k})

k \to \infty lim (1) = 1

k \to \infty lim (\frac{3}{k}) = 0

= 1 + 0

Simplify

= 1

x \to 2 lim (\frac{x ^{2} - 2}{x - 4})

x \to 1 + lim (\frac{x ^{2}}{1 - x ^{2}})

x \to 2 lim ((3 x - 1) (2 x + 5))

t \to 1 lim (2 t - t^{2})

h \to 0 lim (\frac{x ^{2} + h - x ^{2}}{h})

What is the limit as k approaches infinity of 1+3/k ?
The limit as k approaches infinity of 1+3/k is 1