What is the limit as x approaches 3+of (x^2-9)/(x-3) ?

The limit as x approaches 3+of (x^2-9)/(x-3) is 6

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limit as x approaches 3+of (x^2-9)/(x-3)

x \to 3 + lim (\frac{x ^{2} - 9}{x - 3})

6

Solution steps

x \to 3 + lim (\frac{x ^{2} - 9}{x - 3})

Simplify

\frac{x ^{2} - 9}{x - 3} : x + 3

= x \to 3 + lim (x + 3)

Plug in the value

x = 3

= 3 + 3

Simplify

= 6

\frac{x}{5 + x}

\frac{d}{d x} (5 sin (x))

\frac{2 s + 1}{s ^{2} + 1}

\int \frac{e ^{x}}{9 - e ^{2 x}} d x

\frac{d}{d x} (ln (\frac{4 + e ^{x}}{4 - e ^{x}}))

What is the limit as x approaches 3+of (x^2-9)/(x-3) ?
The limit as x approaches 3+of (x^2-9)/(x-3) is 6