What is the limit as x approaches 0 of 5/(ln(x^2)) ?

The limit as x approaches 0 of 5/(ln(x^2)) is diverges

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limit as x approaches 0 of 5/(ln(x^2))

x \to 0 lim (\frac{5}{ln ( x ^{2} )})

diverges

Solution steps

x \to 0 lim (\frac{5}{ln ( x ^{2} )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{5}{ln ( x ^{2} )}) = 0

x \to 0 - lim (\frac{5}{ln ( x ^{2} )}) = \frac{5}{Does not exist}

= diverges

x \to 0 lim (\frac{( 1 + x ^{4} ) - 1}{x})

x \to \infty lim (\frac{tanh ( x )}{x})

x \to \infty + lim (2)

x \to 0 lim (\frac{x}{x ^{3} + 5 x})

x \to 1 - lim (- \frac{1}{x ^{2} + 6 x - 7})

What is the limit as x approaches 0 of 5/(ln(x^2)) ?
The limit as x approaches 0 of 5/(ln(x^2)) is diverges