What is the integral from 0 to 1 of integral from 0 to 1 of e^{2v-1} ?

The integral from 0 to 1 of integral from 0 to 1 of e^{2v-1} is (e^2-1)/(2e)

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integral from 0 to 1 of integral from 0 to 1 of e^{2v-1}

\int_{0}^{1} \int_{0}^{1} e^{2 v - 1} d v d u

\frac{e ^{2} - 1}{2 e}

Decimal Notation

1.17520 \dots

Solution steps

\int_{0}^{1} \int_{0}^{1} e^{2 v - 1} d v d u

\int_{0}^{1} e^{2 v - 1} d v = \frac{e ^{2} - 1}{2 e}

= \int_{0}^{1} (\frac{e ^{2} - 1}{2 e}) d u

\int_{0}^{1} (\frac{e ^{2} - 1}{2 e}) d u = \frac{e ^{2} - 1}{2 e}

= \frac{e ^{2} - 1}{2 e}

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What is the integral from 0 to 1 of integral from 0 to 1 of e^{2v-1} ?
The integral from 0 to 1 of integral from 0 to 1 of e^{2v-1} is (e^2-1)/(2e)