What is area f(x)=x^3+x^2+1,g(x)=2x+1 ?

The answer to area f(x)=x^3+x^2+1,g(x)=2x+1 is 37/12

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area f(x)=x^3+x^2+1,g(x)=2x+1

area

f (x) = x^{3} + x^{2} + 1, g (x) = 2 x + 1

\frac{37}{12}

Decimal Notation

3.08333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} x^{3} + x^{2} + 1 - (2 x + 1) d x

Solve

\int_{- 2}^{1} x^{3} + x^{2} + 1 - (2 x + 1) d x : \frac{37}{12}

The area is:

= \frac{37}{12}

\int \frac{1}{25 - 36 x ^{2}} d x

n = 4 \sum \infty e^{5 - 6 n}

\frac{\partial}{\partial y} (y (1 + ln (x y)))

t y^{^{'}} + t y = 1 - y, y (1) = 0

\int \frac{1}{x - 1} d x

What is area f(x)=x^3+x^2+1,g(x)=2x+1 ?
The answer to area f(x)=x^3+x^2+1,g(x)=2x+1 is 37/12