What is the limit as x approaches 0 of ((1-e^x))/x ?

The limit as x approaches 0 of ((1-e^x))/x is -1

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limit as x approaches 0 of ((1-e^x))/x

x \to 0 lim (\frac{( 1 - e ^{x} )}{x})

- 1

Solution steps

x \to 0 lim (\frac{1 - e ^{x}}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{- e ^{x}}{1})

= x \to 0 lim (\frac{- e ^{x}}{1})

Plug in the value

x = 0

= \frac{- e ^{0}}{1}

Simplify

= - 1

x \to \frac{1}{3} lim ((2 - 3 x)^{2} + 1)

x \to - 5 lim (x^{2} - 6)

x \to \frac{5}{3} lim (x^{3} - 2 x + 3)

θ \to 0 lim (\frac{( sin ( 2 θ ) )}{θ})

x \to 0 + lim ((3 x)^{x^{2}})

What is the limit as x approaches 0 of ((1-e^x))/x ?
The limit as x approaches 0 of ((1-e^x))/x is -1