What is the limit as x approaches 0 of (e^{2x}-1)^x ?

The limit as x approaches 0 of (e^{2x}-1)^x is Does not exist

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limit as x approaches 0 of (e^{2x}-1)^x

x \to 0 lim ((e^{2 x} - 1)^{x})

Does not exist

Solution steps

x \to 0 lim ((e^{2 x} - 1)^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((e^{2 x} - 1)^{x}) = 1

x \to 0 - lim ((e^{2 x} - 1)^{x}) =

Does not exist

= Does not exist

x \to 2 lim (\frac{x ^{2} - 3}{x - 3})

x \to 0 lim (\frac{( 3 - x ) ^{3}}{x})

x \to \infty lim (x^{2} - 16)

x \to 0 lim (\frac{∣ x ∣ + x}{x})

x \to - 3 lim (\frac{x}{x ^{2} + x - 6})

What is the limit as x approaches 0 of (e^{2x}-1)^x ?
The limit as x approaches 0 of (e^{2x}-1)^x is Does not exist