What is the derivative of (2x-3^3) ?

The derivative of (2x-3^3) is 6(2x-3)^2

What is the first derivative of (2x-3^3) ?

The first derivative of (2x-3^3) is 6(2x-3)^2

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\frac{d}{d x} ((2 x - 3)^{3})

6 (2 x - 3)^{2}

Solution steps

\frac{d}{d x} ((2 x - 3)^{3})

Apply the chain rule:

3 (2 x - 3)^{2} \frac{d}{d x} (2 x - 3)

= 3 (2 x - 3)^{2} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= 3 (2 x - 3)^{2} \cdot 2

Simplify

= 6 (2 x - 3)^{2}

\frac{\partial}{\partial x} (4 x + y)

\int 4 e^{2 x - 1} d x

\int_{- 1}^{1} \frac{1}{t + 1} d t

\frac{d y}{d x} = 42 y x^{6}

\int_{0}^{1} (2 x + y)^{8} d x

What is the derivative of (2x-3^3) ?
The derivative of (2x-3^3) is 6(2x-3)^2
What is the first derivative of (2x-3^3) ?
The first derivative of (2x-3^3) is 6(2x-3)^2