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Popular >

area x=-2+4y,x=y^2+1

Solution

area

x = - 2 + 4 y, x = y^{2} + 1

Solution

No Solution

Solution steps

Isolate

y

for

x = - 2 + 4 y : y = \frac{x + 2}{4}

Isolate

y

for

x = y^{2} + 1 : y = x - 1, y = - x - 1

f_{1} (x) = \frac{x + 2}{4}

f_{2} (x) = x - 1

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x + 2}{4} = x - 1 : x = 10, x = 2

\frac{x + 2}{4} = - x - 1 :

No Solution for

x \in R

x - 1 = - x - 1 : x = 1

Curves not bounded

= No Solution

Popular Examples

(\partial)/(\partial x)(10xcos(4xy))

\frac{\partial}{\partial x} (10 x cos (4 x y))

limit as x approaches 0 of ((x+1)^4-1)/x

x \to 0 lim (\frac{( x + 1 ) ^{4} - 1}{x})

integral of xsin(x^2+4)

\int x sin (x^{2} + 4) d x

x(dy)/(dx)-2y=6x^5

x \frac{d y}{d x} - 2 y = 6 x^{5}

y^{''}+6y^'+9y=18t^2+24t+4

y^{^{''}} + 6 y^{^{'}} + 9 y = 18 t^{2} + 24 t + 4

Frequently Asked Questions (FAQ)

What is area x=-2+4y,x=y^2+1 ?
The answer to area x=-2+4y,x=y^2+1 is No Solution