What is the limit as h approaches 0 of (4h-h^2)/(2h) ?

The limit as h approaches 0 of (4h-h^2)/(2h) is 2

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limit as h approaches 0 of (4h-h^2)/(2h)

h \to 0 lim (\frac{4 h - h ^{2}}{2 h})

2

Solution steps

h \to 0 lim (\frac{4 h - h ^{2}}{2 h})

Simplify

\frac{4 h - h ^{2}}{2 h} : \frac{1}{2} (4 - h)

= h \to 0 lim (\frac{1}{2} (4 - h))

Plug in the value

h = 0

= \frac{1}{2} (4 - 0)

Simplify

\frac{1}{2} (4 - 0) : 2

= 2

x \to \infty lim (\frac{72}{x})

x \to 2 - lim (8 - 2 x)

x \to 0.1 lim (\frac{1}{x} + ln (x))

x \to 2 lim (x + y)

x \to 5 lim (\frac{2}{x - 7})

What is the limit as h approaches 0 of (4h-h^2)/(2h) ?
The limit as h approaches 0 of (4h-h^2)/(2h) is 2