What is the limit as x approaches 0+of x^2ln(x)+1 ?

The limit as x approaches 0+of x^2ln(x)+1 is 1

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limit as x approaches 0+of x^2ln(x)+1

x \to 0 + lim (x^{2} ln (x) + 1)

1

Solution steps

x \to 0 + lim (x^{2} ln (x) + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (x^{2} ln (x)) + x \to 0 + lim (1)

x \to 0 + lim (x^{2} ln (x)) = 0

x \to 0 + lim (1) = 1

= 0 + 1

Simplify

= 1

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What is the limit as x approaches 0+of x^2ln(x)+1 ?
The limit as x approaches 0+of x^2ln(x)+1 is 1