What is the derivative of 5sin^2(t) ?

The derivative of 5sin^2(t) is 5sin(2t)

What is the first derivative of 5sin^2(t) ?

The first derivative of 5sin^2(t) is 5sin(2t)

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derivative of

5 sin^{2} (t)

5 sin (2 t)

Solution steps

\frac{d}{d t} (5 sin^{2} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (sin^{2} (t))

Apply the chain rule:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 5 \cdot 2 sin (t) cos (t)

Simplify

5 \cdot 2 sin (t) cos (t) : 5 sin (2 t)

= 5 sin (2 t)

\frac{d}{d x} (4 x sin (x^{2}))

\frac{d}{d x} (\frac{2 - x}{1 - y})

\frac{\partial}{\partial x} (e^{- \frac{x}{2}})

\int \frac{1}{4} sin (4 x) d x

(- 3, 3), (4, - 5)

What is the derivative of 5sin^2(t) ?
The derivative of 5sin^2(t) is 5sin(2t)
What is the first derivative of 5sin^2(t) ?
The first derivative of 5sin^2(t) is 5sin(2t)