What is the derivative of 9/(x+1) ?

The derivative of 9/(x+1) is -9/((x+1)^2)

What is the first derivative of 9/(x+1) ?

The first derivative of 9/(x+1) is -9/((x+1)^2)

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derivative of

\frac{9}{x + 1}

- \frac{9}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 9 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

9 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : - \frac{9}{( x + 1 ) ^{2}}

= - \frac{9}{( x + 1 ) ^{2}}

x \to - 1 lim ((x + 2)^{7} (2 x)^{2})

\frac{\partial}{\partial x} (\frac{3}{2 x + 3 y})

x \to - 4 lim ((x + 3)^{2})

\int \frac{x}{x ^{2} + x + 1} d x

\frac{d}{d x} (- e^{3 x})

What is the derivative of 9/(x+1) ?
The derivative of 9/(x+1) is -9/((x+1)^2)
What is the first derivative of 9/(x+1) ?
The first derivative of 9/(x+1) is -9/((x+1)^2)