What is the sum from n=0 to infinity of (-1/9)^n ?

The sum from n=0 to infinity of (-1/9)^n is 9/10

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sum from n=0 to infinity of (-1/9)^n

n = 0 \sum \infty (- \frac{1}{9})^{n}

\frac{9}{10}

Solution steps

n = 0 \sum \infty (- \frac{1}{9})^{n}

Apply Series Geometric Test:

\frac{9}{10}

= \frac{9}{10}

n = 2 \sum \infty \frac{1}{n ln ^{2} ( n )}

n = 0 \sum \infty \frac{4}{1 + 3 n ^{3}}

n = 0 \sum \infty \frac{n ^{2}}{5 + 2 n}

n = 1 \sum \infty (sin (2))^{n}

n = 1 \sum \infty \frac{1}{5 ^{n} - n}

What is the sum from n=0 to infinity of (-1/9)^n ?
The sum from n=0 to infinity of (-1/9)^n is 9/10