What is the sum from n=0 to infinity of ((1)^n)/n ?

The sum from n=0 to infinity of ((1)^n)/n is diverges

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sum from n=0 to infinity of ((1)^n)/n

n = 0 \sum \infty \frac{( 1 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{1 ^{n}}{n}

Simplify

= n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= diverges

k = 1 \sum \infty \frac{1}{2 k ^{2} + k}

n = 1 \sum \infty \frac{1 ^{n}}{n}

n = 1 \sum \infty (cos (\frac{1}{n}))^{n}

n = 1 \sum \infty \frac{n}{ln ( n )}

n = 3 \sum \infty \frac{1}{2 n ^{2} + n}

What is the sum from n=0 to infinity of ((1)^n)/n ?
The sum from n=0 to infinity of ((1)^n)/n is diverges