What is the sum from n=5 to infinity of (1/2)^n ?

The sum from n=5 to infinity of (1/2)^n is converges

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sum from n=5 to infinity of (1/2)^n

n = 5 \sum \infty (\frac{1}{2})^{n}

converges

Solution steps

n = 5 \sum \infty (\frac{1}{2})^{n}

Apply Series Ratio Test:

converges

= converges

n = 1 \sum \infty \frac{n}{n !}

n = 2 \sum \infty (0.33)^{n}

n = 0 \sum \infty \frac{1}{3 + n}

n = 1 \sum \infty e^{n^{- 2}}

n = 1 \sum \infty \frac{3}{2 n - 1}

What is the sum from n=5 to infinity of (1/2)^n ?
The sum from n=5 to infinity of (1/2)^n is converges