What is the sum from n=1 to infinity of 5/(n!) ?

The sum from n=1 to infinity of 5/(n!) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 5/(n!)

n = 1 \sum \infty \frac{5}{n !}

converges

Solution steps

n = 1 \sum \infty \frac{5}{n !}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{n !}

Apply Series Ratio Test:

converges

= 5 converges

= converges

n = 1 \sum \infty \frac{5}{4 ^{n}}

n = 0 \sum \infty arcsin (n)

n = 1 \sum \infty (4^{\frac{1}{3}})^{n}

n = 1 \sum \infty \frac{6}{n !}

n = 1 \sum \infty (\frac{5}{4})^{n}

What is the sum from n=1 to infinity of 5/(n!) ?
The sum from n=1 to infinity of 5/(n!) is converges